The correct set of four quantum numbers for valence electrons of rubidium atom (Z=37) is

Options

A. `5, 0, 0 +(1)/(2)`
B. `5,1,0,+(1)/(2)`
C. `5,1,1,+(1)/(2)`
D. `5,0,1,+(1)/(2)`

Answer

A

Explanation

Electronic configuration of Rb (atomic no 37)
`1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(10)4p^(6)5s^(1)" "n=5, l=0, m= 0 & s=pm(1)/(2)`