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Energy of electron is given by E=-2.178x...

Energy of electron is given by `E=-2.178xx10^(-18)((Z^(2))/(n^(2)))`J.
Wavelength of light required to excited an electron in an hydrogen atom from level n=1 to n=2 will be `(h=6.62xx10^(-34)J*s and c=3.0xx10^(8)m*s^(-1))`-

A

`1.214xx10^(-7)m`

B

`2.816xx10^(-7)m`

C

`6.500xx10^(-7)m`

D

`8.500xx10^(-7)m`

Text Solution

Verified by Experts

The correct Answer is:
A
`(1)/(lambda)=R_(H^(Z^(2)))((1)/(n_(1)^(2))-(1)/(n_(2)^(2)))," "z=1, n_(1)=n_(1)=1&n_(2)=2, R_(H)=10977cm^(-1)," "lambda=1.2xx10^(-7)m`
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Energy of an electron is given by E = - 2.178 xx 10^-18 J ((Z^2)/(n^2)) . Wavelength of light required to excite an electron in an hydrogen atom from level n = 1 to n = 2 will be (h = 6.62 xx 10^-34 Js and c = 3.0 xx 10^8 ms^-1 ).

Energy of an electron in an excited hydrogen atom is -3.4eV . Its angualr momentum will be: h = 6.626 xx 10^(-34) J-s .

Calculate the energy of an electron having de-Broglie wavelength 5500Å. Given, h=6.62xx10^(-34)Js, m_(e)=9.1xx10^(-31)kg .