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If the shortest wavelength in Lyman seri...

If the shortest wavelength in Lyman series of hydrogen atom is A, then the longest wavelength in Paschen series of `He^(+)` is:

A

`(5A)/(9)`

B

`(9A)/(5)`

C

`(36A)/(5)`

D

`(36A)/(7)`

Text Solution

Verified by Experts

The correct Answer is:
D
Shortest wavelength transition in Lyman series will be corresponding to
`n=oo rarrn=1" "(1)/(lambda)=R_(H)(1)^(2)[(1)/(1^(2))-(1)/(oo^(2))]," "lambda=(1)/(R_(H))`
Given wavelength for this transition is A therefore `(1)/(R_(H))=A" ...(i)"`
Longest wavelength transition for `He^(+)` in Pachen series `4rarr3`
`(1)/(lambda)=R_(H)(2)^(2)[(1)/(3^(2))-(1)(4^(2))]`
Putting value of `R_(H)` from equation (i) `lambda=(36A)/(7)`
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