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The de Broglie wavelenght (lambda) assoc...

The de Broglie wavelenght `(lambda)` associated with a photoelectron varies with the frequency `(v)` of the incident radiation as,[`v_(0)` is threshold frequency]:

A

`lambda prop (1)/((v-v_(0))^((3)/(2)))`

B

`lambda prop (1)/((v-v_(0))^((1)/(4)))`

C

`prop (1)/((v-v_(0))^((1)/(2)))`

D

`lambda prop (1)/((v-v_(0)))`

Text Solution

Verified by Experts

The correct Answer is:
C
`E=hupsilon," "(h upsilon-hr_(0))="K.E. (from photoelectric effect )"`
`lambda=(h)/(sqrt(2mK.E))," "lambda prop (h)/(sqrt((upsilon-upsilon_(0)))) rArr lambda prop (1)/((upsilon-upsilon_(0)^(1//2)))`
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