The correct set of quantum numbers for the unpaired electron of chlorine atom is :

Options

A. `{:(n,l,m),(2,1,0):}`
B. `{:(n,l,m),(2,1,1):}`
C. `{:(n,l,m),(3,1,1):}`
D. `{:(n,l,m),(3,0,0):}`

Answer

C

Explanation

`Cl(17)=1s^(2)2s^(2)2p^(6)3s^(2)3p^(5)`

The last, unpaired electron has, `n=3, l=1(p)` and m can have any of the three value `(-1,0,+1)`