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If the nitrogen atom has electronic conf...

If the nitrogen atom has electronic configuration `1s^(7)`, it would have energy lower than that of the normal ground state configuration `1s^(2)2s^(2)2p^(3)` because the electrons would be closer to the nucleus. Yet `1s^(7)` is not observed because it violates

A

Heisenberg uncertainty principle

B

Hund’s rule

C

Pauli exclusion principle

D

Bohr postulate of stationary orbits

Text Solution

Verified by Experts

The correct Answer is:
C
`1s^(7)` violate Pauli exclusion principle, according to which an orbital cannot have more than two electrons.
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