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The ionization potential of hydrogen is ...

The ionization potential of hydrogen is 13.60 eV. Calculate the energy in kJ required to produce 0.1 mole of `H^(+)` ions. Given, `1 eV = 96.49 kJ mol^(-1)` .

Text Solution

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Given I.P. = 13.60 eV / atom
`I.P. = 13.60 xx 96.49 // "mole" = 1312 . 264 ` kJ/mole
No of atoms corresponding to 0.1 mole `H^(+) rArr 6.023 xx 10^22`
So for 1 mole atom ionization energy = 1312.264 kJ
For ` 6.023 xx 10^22 " atom is " = (1312.264 xx 6.023)/(6.023 xx 10^23) xx 10^22 = 1312.2 kJ`
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