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EN of the element (A) is E(1) and IP is ...

EN of the element (A) is `E_(1)` and IP is `E_(2)`. Then EA will be

A

`2E_1 - E_2`

B

`E_1 - E_2`

C

`E_1 - 2E_2`

D

`(E_1 + E_2)//2`

Text Solution

Verified by Experts

The correct Answer is:
A
According to Mulliken scale `rArr EA = 2EN - IE = 2E_1 - E_2`
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