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Aqueous solution of two compounds M(1) -...

Aqueous solution of two compounds `M_(1) - O - H and M_(2) - O - H` are prepared in two different beakers . If electronegativity of `M_(1) = 3.4, M_(2) = 1.2, 0 = 3.5 and H = 2.1`, then the nature of two solution will be respectively

A

acidic, basic

B

acidic, acidic

C

basic, acidic

D

basic, basic

Text Solution

Verified by Experts

The correct Answer is:
A
The electronegativity difference between `M_1` and O is 0.1, which indicates `M_1 - O` bond will be covalent, since O - H bond having more ionic character thus bond will break and `H^(+)` ions will release and acidic solution is formed. Whereas difference between electronegativity of `M_2 - O` bond is 2.3, thus, `M_2 - OH` bond will break. Hence solution will be basic in nature.
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