An element with molar mass `2.7xx10^(-2)` kg per mole forms a cubic unit cell with edge length 405 pm. If its density is `2.7xx10^(3)` , what is the nature of the cubic unit cell ?

Explanation

To determine the nature of the cubic unit cell for the given element, we will follow these steps:

### Step 1: Convert Given Values
- **Molar Mass (M)**: \(2.7 \times 10^{-2} \, \text{kg/mol}\)
- **Edge Length (a)**: \(405 \, \text{pm} = 405 \times 10^{-12} \, \text{m} = 4.05 \times 10^{-10} \, \text{m}\)
- **Density (\(\rho\))**: \(2.7 \times 10^{3} \, \text{kg/m}^3\)

### Step 2: Use the Density Formula
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