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Niobium crystallizes in body-centred cub...

Niobium crystallizes in body-centred cubic structure. If the density is `8.55 g cm^(-3)`, calculate the atomic radius of niobium using its atomic mass `93 u`.

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`a^(3) = (MxxZ)/(rhoxxN_(0)xx10^(-30))= (93"gmol"^(-1)xx2)/(8.55 "g cm"^(-3)xx6.02xx10^(23)"mol"^(-1)xx10^(-30))= 3.61xx10^(7)= 36.1xx10^(6)`
`:. A= (36.1^(1//3)xx10^(2) pm = 3.304xx10^(2) pm = 330.4` pm
`[ x = (36.1)^(1//3), "log" x = (1)/(3) "log" 36.1 = (1)/(3) 1.5575 = 0.519 ` or x = antibg 0.519 = 3.304 ]
For body - centred cubic `x =(sqrt(3))/(4) a = 0.433 a = 0.433xx330.3 pm = 1431 ` pm.
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