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Each rubidium halide crystallising in th...

Each rubidium halide crystallising in the NaCl-type lattice has a unit cell length `0.30 Å` greater than that for corresponding potassium salt `(r_(k+)=1.33 Å`) of the same halogen. Hence, ionic radius of `Rb^(+)` is

A

`1.18 Å`

B

`1.43 Å`

C

`1.63 Å`

D

`1.03 Å`

Text Solution

AI Generated Solution

To find the ionic radius of \( Rb^+ \) given the information about the unit cell lengths and the ionic radius of \( K^+ \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Problem**: We know that the unit cell length of rubidium halides is \( 0.30 \, \text{Å} \) greater than that of the corresponding potassium halides. The ionic radius of \( K^+ \) is given as \( r_{K^+} = 1.33 \, \text{Å} \). 2. **Convert the Unit Cell Length Difference**: ...
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