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KCl crystallises in the same type of lat...

KCl crystallises in the same type of lattice as does NaCl Given that `r_(Na^(+))//r_(Cl^(-))=0.55` and `r_(K^(+))//r_(Cl^(-))=0.74`, the ratio of the side of unit cell for KCl to that of NaCl is

A

1.123

B

0.0891

C

1.414

D

0.414

Text Solution

Verified by Experts

Given `r_(Na^(+))//r_(cr^(-))=0.55, r_(K^(+))//r_(cr^(-))=0.74`
`(r_(KC1))/(r_(NaC1))=?`
`(r_(Na^(+)))/(r_(CI^(-)))`=0.55
`(r_(Na^(+)))/(r_(CI^(-)))+1=0.55+1`
`(r_(Na^(+))+r_(CI^(-)))/(r_(CI^(-)))=1.55`
` (r_(K^(+)))/(r_(CI^(-)))=0.74`
`(r_(K^(+)))/(r_(CI^(-)))+1=0.74+1`
`(r_(K^(+))+r_(CI^(-)))/(r_(CI))=1.74`
Eq. (ii) divide by Eq. (i) `(r_(K^(+))+r_(CI^(-)))/(r_(Na^(+))+r_(CI^(-)))=(1.74)/(1.55)=1.1226.`
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KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

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