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In the lattice parameter of Si = 5.43 Å ...

In the lattice parameter of `Si = 5.43 Å` and the mass of `Si` atom is `28.08 xx 1.66 xx10^(-27) kg`, the density of silicon in `kg m^(-3)` is (Given: Silicon has diamondcubic structure)

A

2330

B

1115

C

3445

D

1673

Text Solution

Verified by Experts

Si has FCC structure and Si atoms are present in alternate tetrahedral voids. So the total number of atoms = 8
`(("no.ofatoms")xx("mass of one atom"))/("volumeof unit celll")`
density`= (8xx(28.08xx1.66xx10^(-27))"kg")/((5.43xx10^(-10))^(3)m^(2))=2330 "kgm^(-3)`
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