An fcc lattice has a lattice parameter `a = 400` pm. Calculater the molar volume of the lattice including all the empty space.

Options

A. 10.8 mL
B. 96 mL
C. 8.6 mL
D. 9.6 mL

Explanation

No. of atoms =`N_(a) implies` No. of unit cells =`(N_(a))/(4) " " [ because ` 4 atoms in each unit cell]
Volume of 1 mole lattice `(N_(a))/(4)xx` volume of unit cell
`=(6.023xx10^(23))/(4) xx(400xx10^(-12))^(3)m^(3)=9.64 mL`