Home
Class 12
CHEMISTRY
A compound AB has a rock salt type struc...

A compound AB has a rock salt type structure with A:B=1:1 . The formula weight of AB is 6.023 y amu and the closest A-B distance is `y^(1//3)` nm. Calculate the density of lattice (in `kg//m^(3))`

Text Solution

Verified by Experts

AB has rock salt structure A:B=1:1 i.e. structure (Z = 4) and formula weight of AB is g having closest distance (between A-B) = `Y^((1)/(3))`nm. Therefore, edge length of unit cell `= 2 (r_(A^(+))+r_(B^(-)))= 2xxY^(1//3)xx10^(-9)m`
Density of AB = `(4xx6.023Yxx10^(-3))/(6.023xx10^(23)xx(2Y^(1//3)xx10^(-9))^(3))=5"Kgm"^(-3).`
Promotional Banner

Similar Questions

Explore conceptually related problems

A compount AB has a rock type structure with A:B=1:1 . The formula weight of AB is 6.023 Y am u and the closed A-B distance is Y^(1//3) nm. (i) Find the density of lattice. (ii) If the density of lattice is found to be 20 kg m^(-3) , then predict the type of defect.

The crystal AB (rock salt structure) has molecular weight 6.023 y u, where y is an arbitrary number in u. If the minimum distance between cation and anion is y^(1//2) nm and the observed density is 20kg/ m^(3) , find the (i) density in kg/ m^(3) and (ii) type of defect.

A solid AB has rock salt structure. How many atoms of A and B are present in the unit cell ?