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A metal crystallises in a face centred c...

A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is 'a' the closest approach between two atoms in metallic crystal will be

A

`(a)/(sqrt(2))`

B

2a

C

`2sqrt(2)`a

D

`sqrt(2)`a

Text Solution

Verified by Experts

In FCC distance of closest approach between two atoms = 2r
In FCC, atoms are in close contact along face diagonal of FCC unit cell.
`therefore " " 4r = sqrt(2) a " " rArr 2r = (sqrt(2)a)/(2) = ((a)/(sqrt(2)))`
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