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A metal crystallises in a face centred c...

A metal crystallises in a face centred cubic structure. If the edge length of its unit cell is 'a' the closest approach between two atoms in metallic crystal will be

A

`sqrt(2)`a

B

`(a)/(sqrt(2))`

C

2a

D

`2sqrt(2)`a

Text Solution

Verified by Experts

For fcc,
then b = 4r = `sqrt(2)`a
a = `(4r)/(sqrt(2)) = 2 sqrt(2)r rArr r = (a)/(2sqrt(2))`
Therefore, distance of closest approach
= ` 2r xx (a)/(2sqrt(2)) = (a)/(sqrt(2))`
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