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An element has a face-centred cubic (fcc...

An element has a face-centred cubic (fcc) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is:

A

`sqrt(2)`a

B

`(a)/(sqrt(2))`

C

a

D

`(3)/(2)`a

Text Solution

Verified by Experts

`cos theta = (1)/(sqrt(3))`
The distance of corner atom tetrahedral void along body diagonal = Component along any side = `(sqrt(2) a)/(4 ) xx (1)/(sqrt(3)) = (a)/(4)`
`(a - (a)/(4) - (a)/(4)) = (a)/(2)`
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