Home
Class 12
PHYSICS
A force F is applied on a block kept at ...

A force F is applied on a block kept at the smooth surface in contact with the wall. If the block is at rest, the forces applied by block on surface (1) is `F_(1)` and on surface (2) is `F_(2)`. Find `(F_(1))/(F_(2))` (Take g=10 `m//s^(2))`

A

`2:1`

B

`1:2`

C

`1:1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
a

`N_(1)`=Normal reaction applied by surface 1 on block =`f_(1)`
`N_(1)=100sqrt(2) cos 45^(@)+100=100+100`
`N_(1)=200 N`
fore applied by block = action / Reaction pari =200 N
`F_(2)=100 N=N_(2) , (F_(1))/(F_(2))=2.1`
Promotional Banner

Similar Questions

Explore conceptually related problems

A single horizontal force F is applied to a block of mass M_(1) which is in contact with another block of mass M_(2) . If the surfaces are frictionless, the force between the blocks is

A force F is applied on block A and B and between the blocks B and C respectively are (Assume frictionless surface)

For a block kept on a table, the maximum force of static friction is F_(1) . If the set-up is taken to moon, the force is F_(2) . Then

A block of mass 10 kg is placed on a horizontal surface as shown in the figure and a force F = 100 N is applied on the block as shown, in the figure. The block is at rest with respect to ground. If the contact force between block and ground is 25n (in Newton) then value of n is : (Take g = 10 m//s^(2))

A block placed on a rough horizontal surface is pulled by a horizontal force F Let f be the force applied by the rough surface on the block . Plot a graph of f versus F .

Anoop pushes eight identical blocks on the horizontal frictionless surface with horizontal force F. the that block-1 (where F is applied) exerts on block 2 has magnitudes F_(21) and the force that block-7exerts on the block -8 is F_(87) . Find (F_(21))/(F_(87))

Ram pushes eight identical blocks on the horizontal frictionless surface with horizontal force F. The force that block-1 exerts at block-2 has magnitude F_(21) and the force that block-7 exerts on the block-8 is F_(87) find (F_(21))/(F_(87))

A force F is applied on a block of mass sqrt(3) kg which rests on a horizontal surface with a coefficient of friction 1/(2sqrt3) . The maximum value of F for which the block doesn't move, is [Take g = 10 ms^(-2)]