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The resultant of vecP and vecQ is perpen...

The resultant of `vecP` and `vecQ` is perpendicular to `vecP`. What is the angle between `vecP` and `vecQ`

A

`cos^(-1)(P//Q)`

B

`cos^(-1)(P//Q)`

C

`sin^(-1)(P//Q)`

D

`sin^(-1)(-p//Q)`

Text Solution

Verified by Experts

The correct Answer is:
b
`sin 90^(@)=(Q sin theta)/(R )` Let R : m agnitude of `bar P` & `barQ`) squaring both side
`rarr P^(2)+Q^(2)+2PQ cos theta = Q^(2) sin^(@) theta rarr (P+Q cos theta)^(2)=0 rarr theta = cos^(-1) (-P/Q)`
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