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A large hemi sphere of radius 100m is fi...

A large hemi sphere of radius 100m is fixed on the ground. A man weighing 700 N stands a at height of 50m above the ground. N and f represent the normal and frictional force acting on him. Then :

A

N=700 N, F=0

B

N=350 N, F=350 N

C

N=350 N,F=`350sqrt(3)` N

D

N=`350sqrt(3)`,F=350 N

Text Solution

Verified by Experts

The correct Answer is:
c
Since slipping tendency is down the plane friction acts up the plane in `triangle` OAM
`cos theta =50/100 rarr theta =60^(@)`
`rarr N= 700 cos 60^(2) =350 N`
`F=700 sin 60 =350 sqrt(5) N`
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