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Twelve balls are distribute among three boxes. The probability that the first box contains three balls is `(110)/9(2/3)^(10)` b. `(110)/9(2/3)^(10)` c. `(^(12)C_3)/(12^3)xx2^9` d. `(^(12)C_3)/(3^(12))`

A

`(110)/(9) ((2)/(5))^(10)`

B

`(9)/(110) ((2)/(3))^(10)`

C

`(""^(12) C_(3))/(12^(3)) 2^(9)`

D

`(""^(12) C_(3))/(3^(12))`

Text Solution

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The correct Answer is:
A
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