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Find the probability of drawing two spad...

Find the probability of drawing two spades from a well shuffled pack of 52 cards if :
(I) the first card is replaced before the second is taken (II) First card is not replaced

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To solve the problem of finding the probability of drawing two spades from a well-shuffled pack of 52 cards under two different scenarios, we will break it down step by step. ### Step 1: Understand the total number of cards and spades A standard deck of cards contains 52 cards, out of which there are 13 spades. ### Step 2: Case I - First card is replaced before the second is taken 1. **Probability of drawing the first spade**: - The number of favorable outcomes (drawing a spade) = 13 - Total outcomes = 52 - Probability of drawing the first spade = \( P(A) = \frac{13}{52} = \frac{1}{4} \) 2. **Probability of drawing the second spade (after replacement)**: - Since the first card is replaced, the total number of cards remains 52 and the number of spades remains 13. - Probability of drawing the second spade = \( P(B) = \frac{13}{52} = \frac{1}{4} \) 3. **Combined probability for both events**: - Since the two events are independent (due to replacement), the combined probability is: \[ P(A \text{ and } B) = P(A) \times P(B) = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \] ### Step 3: Case II - First card is not replaced 1. **Probability of drawing the first spade**: - As in the first case, the probability of drawing the first spade remains the same: \[ P(A) = \frac{13}{52} = \frac{1}{4} \] 2. **Probability of drawing the second spade (without replacement)**: - After drawing the first spade, there are now 12 spades left and only 51 cards remaining. - Probability of drawing the second spade = \( P(B|A) = \frac{12}{51} \) 3. **Combined probability for both events**: - The combined probability is: \[ P(A \text{ and } B) = P(A) \times P(B|A) = \frac{1}{4} \times \frac{12}{51} = \frac{12}{204} = \frac{1}{17} \] ### Final Answers: - **Case I (with replacement)**: The probability of drawing two spades is \( \frac{1}{16} \). - **Case II (without replacement)**: The probability of drawing two spades is \( \frac{1}{17} \). ---
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