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Let A, B and C be three events such that...

Let A, B and C be three events such that `P(A)=0.3, P(B)=0.4, P(C )=0.8, P(A cap B)=0.08, P(A cap C) =0.28, P(A cap B cap C)=0.09`. If `P(A cup B cup C) ge 0.75`, then show that `P(B cap C)` satisfies

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The correct Answer is:
`(0.48)`
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