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Ea n dF are two independent events. The ...

`Ea n dF` are two independent events. The probability that both `Ea n dF` happen is 1/12 and the probability that neither `Ea n dF` happens is 1/2. Then, `P(E)=1//3, P(F)=1//4` `P(E)=1//4, P(F)=1//3` `P(E)=1//6, P(F)=1//2` `P(E)=1//2, P(F)=1//6`

A

`P(E ) = (1)/(3), P(F) = (1)/(4)`

B

`P(E ) = (1)/(2), P(F) = (1)/(6)`

C

`P(E ) = (1)/(6), P(F) = (1)/(2)`

D

`P(E ) = (1)/(4), P(F) = (1)/(3)`

Text Solution

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The correct Answer is:
A, C
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