If A^(-1)=[(1,-1,2),(0,3,1),(0,0,-1//3)]...

If `A^(-1)=[(1,-1,2),(0,3,1),(0,0,-1//3)]`, then

A

|A|=-1

B

adjA=`[(-1,1,-2),(0,-3,-1),(0,0,1//3)]`

C

`A=[(1,1//3,7),(0,1//3,1),(0,0,-3)]`

D

`A=[(1,-1//3,-7),(0,-3,0),(0,0,1)]`

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The correct Answer is:

A, B, C

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