Home
Class 12
MATHS
If the system of equations ax+hy+g=0 …...

If the system of equations
ax+hy+g=0 ….(i)
hx+by+f=0…(ii)
and `ax^2+2hxy+by^2 + 2gx+ 2fy+c+t=0`….(iii)
has a unique solution and `(abc+2fgh-af^2-bg^2-ch^2)/(h^2-ab)=8` , find the value of 't'.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem step by step, we will analyze the equations and use the provided condition to find the value of 't'. ### Step 1: Understand the system of equations We have the following equations: 1. \( ax + hy + g = 0 \) (Equation 1) 2. \( hx + by + f = 0 \) (Equation 2) 3. \( ax^2 + 2hxy + by^2 + 2gx + 2fy + c + t = 0 \) (Equation 3) The system has a unique solution, which implies that the determinant of the coefficients of the first two equations must be non-zero. ### Step 2: Find the determinant condition for unique solutions The determinant \( D \) of the coefficients from the first two equations can be calculated as follows: \[ D = \begin{vmatrix} a & h \\ h & b \end{vmatrix} = ab - h^2 \] For the system to have a unique solution, we require: \[ D \neq 0 \implies ab - h^2 \neq 0 \] ### Step 3: Use the given condition We are given the condition: \[ \frac{abc + 2fgh - af^2 - bg^2 - ch^2}{h^2 - ab} = 8 \] We can rearrange this to find \( t \): \[ abc + 2fgh - af^2 - bg^2 - ch^2 = 8(h^2 - ab) \] ### Step 4: Express \( t \) in terms of the other variables From Equation 3, we can express \( t \): \[ t = - (ax^2 + 2hxy + by^2 + 2gx + 2fy + c) \] Substituting the expression we derived from the condition into this equation gives us: \[ t = - (abc + 2fgh - af^2 - bg^2 - ch^2) + 8(h^2 - ab) \] ### Step 5: Substitute and simplify Now, we can substitute the expression from the condition into our expression for \( t \): \[ t = - (abc + 2fgh - af^2 - bg^2 - ch^2) + 8(h^2 - ab) \] This means that \( t \) can be expressed as: \[ t = - (abc + 2fgh - af^2 - bg^2 - ch^2) + 8h^2 - 8ab \] ### Step 6: Final value of \( t \) Since we know that the left-hand side of the condition equals \( 8(h^2 - ab) \), we can conclude that: \[ t = 8(h^2 - ab) - (abc + 2fgh - af^2 - bg^2 - ch^2) \] Thus, substituting the known values will yield the final value of \( t \). ### Conclusion The value of \( t \) is determined by the relationship established through the equations and the condition provided.
Promotional Banner

Similar Questions

Explore conceptually related problems

ax^2+2hxy+by^2+2gx+2fy+c=0

The equations a^2x^2+2h(a+b)xy+b^2y^2=0 and ax^2+2hxy+by^2=0 represent.

the equation ax^(2)+ 2hxy + by^(2) + 2gx + 2 fy + c=0 represents an ellipse , if

If the equation ax^2 +2hxy + by^2 = 0 and bx^2 - 2hxy + ay^2 =0 represent the same curve, then show that a+b=0 .

If the pair of lines ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 intersect on the y-axis,then prove that 2fgh=bg^(2)+ch^(2)

The principal axes of the hyperbola ax^(2) + 2hxy + by^(2) + 2gx + 2fy + c = 0 are parallel to the lines

The equation ax^(2)+2hxy+by^(2)+2gx+2fy+c=0 represents a circle if

If the centre of the hyperbola whose equation is ax^(2) + 2hxy + by^(2) + 2gx + 2fy + c = 0 " be " (alpha, beta) , then find the equation of the asymptotes.

Derive a method to find separate equation of pair of lines given by ax^(2)+2hxy+by^(2)+2gx+2fy+c=0