[" Let "ABC" is triangle whose vertices are "A(1,-1),B(0,2),C(x^(2),y')" and area of "],[Delta ABC" is "5" and "C(x',y')" lies on "3x+y-4 lambda=0" then "]

Let ABC is a triangle whose vertices are A(1, –1), B(0, 2), C(x', y') and area of triangleABC is 5 and C(x', y') lie on 3x + y – 4lambda = 0 , then

Let ABC is a triangle whose vertices are A(1, –1), B(0, 2), C(x', y') and area of triangleABC is 5 and C(x', y') lie on 3x + y – 4lambda = 0 , then

Consider the triangle ABC with vertices A(1,2,3),B(-1,0,4),C(0,1,2) Find the area of the triangle ABC.

Let two points be A(1,-1) and B(0,2) .If a point P(h,k) be such that the area of Delta PAB=5 sq units and it lies on the line 3x+y-4 lambda=0 then a value of lambda is

Let two points be A(1,-1) and B(0,2) .If a point P(h,k) be such that the area of triangle PAB is 5 sq units and it lies on the line 3x+y-4 lambda =0 ,then the value of lambda is

Using integration, find the area of the triangle ABC whose vertices are A(-1,1), B(0,5) and C(3,2) .

Using integration, find the area of the triangle ABC whose vertices are A(-1,1), B(0,5) and C(3,2) .

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))B(x_(2),y_(2)) is

The area of the triangle OAB with vertices O(0,0),A(x_(1),y_(1))" and B(x_(2),y_(2)) is