Home
Class 13
CHEMISTRY
[20.0mL" of "0.1MH(2)SO(4)" solution is ...

[20.0mL" of "0.1MH_(2)SO_(4)" solution is "],[" added to "30.0mL" of "0.2M" of "],[NH_(4)OH" solution.The "pH" of resulting "],[" mixture: (pkb of "NH_(4)OH" is 4.7) "]

Promotional Banner

Similar Questions

Explore conceptually related problems

20mL of 0.1M(H_(2)SO_(4)) solution is added to 30mL of 0.2M(NH_(4)OH) soulution. The ._(p)H of the resultant mixture is : [(p)k_(b) " of " NH_(4)OH=4.7] .

20mL of 0.1M(H_(2)SO_(4)) solution is added to 30mL of 0.2M(NH_(4)OH) soulution. The ._(p)H of the resultant mixture is : [._(p)k_(b) " of " NH_(4)OH=4.7] .

20 mL of 0.1 M H_2SO_4 solution is added to 30 mL of 0.2 M NH_4OH solution. The pH of the resultant mixture is : [ pK_b of NH_4OH =4.7]

Amount of (NH_(4))_(2)SO_(4) which must be added to 50mL of 0.2 M NH_(4)OH solution to yield a solution of pH 9.26 is ( pK_(b) of NH_(4)OH=4.74 )

A solution contains 60 mL of 0.1 M NH_(4)OH and 30 mL of 0.1 MHCl . The P^(H) of the resulting mixture is (Given K_(b) of NH_(4)OH = 1.8 xx 10^(-5) , 1.8 = 0.2553 )

If 200 ml of 0.031 M solution of H _(2) SO_(4) is added to 84 ml of a 0.150 M KOH solution. What is the pH of the resulting solution? (log 7 = 0.845)

If 200 ml of 0.031 M solution of H _(2) SO_(4) is added to 84 ml of a 0.150 M KOH solution. What is the pH of the resulting solution? (log 7 = 0.845)

50 ml of 0.2 M NH_(4)OH and 50 ml of 0.2 M HCl solutions are Mixed. pH of the resulting solution is (Given Kb of NH_(4)OH=1 times 10^(-5) )

50 ml of 0.1 MH_(2)SO_(4) were added to 100 ml of 0.2 MHNO_(3) . Then the solution is diluted to 300 ml. What is the pH of the solution?