cos(2sin^(- 1)1/3)=?...

`cos(2sin^(- 1)1/3)=?`

Verified by Experts

Given,
`cos(2sin^(−1)(1/3))`
Let `sin^(−1) (1/3)=theta`
`=>sintheta=1/3`
`=>sin^2theta=1/9`
`cos(2sin^(−1) (1/3)`
`=cos(2theta)`
`=1−2sin^2theta`
...

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