The dimensions of a conductor of specific resistance p are shown. Find the resistance of the conductor across AB, CD and EF.

Explanation

`R_(AB)=(rhoc)/(ab),R_(CD)=(rhob)/(ac),R_(EF)=(rhoa)/(bc)`
`=(rhoL^(2))/(pi)[{r_(1)L+(r_(2)-r_(1))X}^(-1)]_(0)^(L)(-(I)/((r_(2)-r_(1))))`
`=(-rhoL)/(pi(r_(2)-r_(1)))((1)/(r_(2))-(1)/(r_(1)))-(rhoL)/(pi(r_(1)r_(2)))`
`thereforeV=IR=(IrhoL)/(pir_(1)r_(2))`