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Find the current in 2 Omega resistance....

Find the current in `2 Omega` resistance.

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`2Omega,1Omega` in series `=3Omega`
`3Omega,6Omega` in parallel `=(18)/(9)=2Omega`
`2Omega,4Omega` in series `=6Omega`
`6Omega,3Omega` is parallel `=2Omega`
`R_(eq)=4+4+2=10Omega`

`i=(120)/(10)=12A`
So current in `2Omega` Resistance `=(8)/(3)A`
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