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A galvanometer has resistance 100 Omega ...

A galvanometer has resistance `100 Omega` and it requires current `100 muA` for full scale deflection. A resistor `0.1 Omega` is connected to make it an ammeter. The smallest current required in the circuit to produce the full scale deflection is

A

1000 .1 mA

B

1.1 mA

C

10.1 mA

D

100. mA

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • A galvanometer having resistance of 50 Omega requires a current of 100 Omega A to given full scale deflection. How much resistance is required to convert it into an ammeter of range of 10 A ?

    A
    `5xx10^(-3)Omega` in series
    B
    `5xx10^(-4)Omega` in parallel
    C
    `10^(5)Omega` in series
    D
    `10^(5)Omega` in parallel

  • A galvanometer of resistance 99 Omega requires 5 mA current for full scale deflection. It can be converted into an ammeter of range 0.5 A by connecting a shunt resistance of

    A
    `3 Omega`
    B
    `1 Omega`
    C
    `2 Omega`
    D
    `4 Omega`

  • A galvanometer coil has a resistance of 15 Omega and the metre shows full scale deflection for a current of 4 mA. To convert the meter into a voltmeter of range 0 to 18 V, the required resistance is

    A
    `5885 Omega "in series"`
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    `4485 Omega "in series"`
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