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The moment of inertia of a sphere of rad...

The moment of inertia of a sphere of radius R about an axis passing through its centre is proportional to-

A

`R^2`

B

`R^3`

C

`R^4`

D

`R^5`

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To solve the problem of determining how the moment of inertia of a sphere of radius \( R \) about an axis passing through its center is proportional, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Moment of Inertia**: The moment of inertia \( I \) of an object is a measure of how difficult it is to change its rotational motion about a given axis. For a solid sphere, the moment of inertia about an axis through its center is given by the formula: \[ I = \frac{2}{5} m R^2 \] where \( m \) is the mass of the sphere and \( R \) is its radius. 2. **Identifying Proportionality**: From the formula, we can see that the moment of inertia \( I \) is directly proportional to the mass \( m \) and the square of the radius \( R^2 \). Therefore, we can express this relationship as: \[ I \propto m R^2 \] 3. **Considering Mass**: If we consider a uniform sphere, the mass \( m \) can be expressed in terms of the density \( \rho \) and volume \( V \). The volume \( V \) of a sphere is given by: \[ V = \frac{4}{3} \pi R^3 \] Thus, the mass can be expressed as: \[ m = \rho V = \rho \left(\frac{4}{3} \pi R^3\right) \] 4. **Substituting Mass into Moment of Inertia**: Substituting the expression for mass into the moment of inertia formula gives: \[ I = \frac{2}{5} \left(\rho \frac{4}{3} \pi R^3\right) R^2 \] Simplifying this, we find: \[ I = \frac{2}{5} \cdot \rho \cdot \frac{4}{3} \pi R^5 \] 5. **Final Proportionality**: From the above expression, we can see that the moment of inertia \( I \) is proportional to \( R^5 \) when considering the density and volume of the sphere. However, if we are only looking at the relationship of \( I \) with respect to \( R \), we can conclude: \[ I \propto R^2 \] This indicates that the moment of inertia is proportional to the square of the radius. ### Conclusion: The moment of inertia of a sphere of radius \( R \) about an axis passing through its center is proportional to \( R^2 \).
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MOTION-ROTATIONAL MOTION -Exercise - 1
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  8. Three thin uniform rods each of mass M and length L and placed along t...

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  9. Three rings, each of mass P and radius Q are arranged as shown in the ...

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  10. The torque needed to produce an angular acceleration of 18rad/"sec"^2 ...

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  11. The product of moment of inertia (I) and angular acceleration (alpha) ...

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  12. A disc of radius 2m and mass 200kg is acted upon by a torque 100N-m. I...

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  13. The dimensions of torque are :

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  14. On applying a constant torque on a body-

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  15. A wheel starting with angular velocity of 10 radian/sec acquires angu...

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  16. When a steady toqrue or couple acts on a body, the body

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  17. The radius of gyration of a body depends upon

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  18. Equivalent to force in rotational motion is

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  19. Torque/moment of inertia equals to

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  20. The angular velocity of a body is vec (omega)- = 2 hat(i) + 3 hat(j) ...

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