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Total radiations incident on body = 400 ...

Total radiations incident on body = `400 J`, `20%` radiation reflected and `120` J absorbs. Then find out `%` of transmittive power

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`Q = Q_t + Q_r + Q_a rArr 400 = 80 + 120 + Q_t`
`rArr Q_t = 200 rArr` is 50%
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MOTION-HEAT TRANSFER & THERMAL EXPANSION -Exercise - 3 Section-B
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