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25% absorb, 25 Cal passes out transmits ...

25% absorb, 25 Cal passes out transmits and total incident radiation Q = 500 J Then find out % of reflective power

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To solve the problem step by step, we will analyze the given information and apply the principles of heat transfer and energy conservation. ### Step 1: Understand the given data - Total incident radiation (Q) = 500 J - Percentage of radiation absorbed = 25% - Transmitted radiation (QT) = 25 Cal ### Step 2: Calculate the absorbed radiation (QA) ...
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MOTION-HEAT TRANSFER & THERMAL EXPANSION -Exercise - 3 Section-B
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  2. Which of the following is more close to a black body ?

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  3. Infrared radiation is detected by

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  4. Two spheres of the same material have radii 1m and 4m and temperatures...

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  5. The earth radiates in the infra-red region of the spectrum. The spectr...

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  6. According to Newton's law of cooling, the rate of cooling of a body is...

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  7. If the temperature of the sun were to increase form T to 2T and its ra...

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  8. A radiation of energy E falls normally on a perfctly refelecting surfa...

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  9. The temperature of the two outer surfaces of a composite slab consisti...

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  10. The figure shows a system of two concentric spheres of radii r1 and r2...

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  11. Assuming the Sun to be a spherical body of radius R at a temperature o...

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  12. One end of a thermally insulated rod is kept at a temperature T1 and t...

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  13. A long metallic bar is carrying heat from one of its ends to the other...

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  14. A long metallic bar is carrying heat from one of its ends to the other...

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  15. A liquid in a beaker has temperature theta(t) at time t and theta0 is ...

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  16. If a piece of metal is heated to temperature theta and the allowed to ...

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  17. Three rods of Copper, Brass and Steel are welded together to from a Y ...

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  18. Consider a spherical shell of radius R at temperature T. The black bod...

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  19. A pendulum clock loses 12s a day if the temperature is 40^@C and gains...

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  20. Statement-1: The temperature dependence of resistance is usually given...

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