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Two bodies P and Q have thermal emissivi...

Two bodies P and Q have thermal emissivities of `varepsilon_(P) and varepsilon_Q` respectively. Surface areas of these bodies are same and the total radiant power is also emitted at the same rate. If temperature of P is `theta_P` kelvin then temperature of Q i.e. `theta_Q` is

A

`((epsi_(Q))/(epsi_(p)))^(1//4) theta_(p)`

B

`((epsi_(p))/(epsi_(Q)))^(1//4) theta_(p)`

C

`((epsi_(Q))/(epsi_(p)))^(1//4) xx (1)/(theta_(p))`

D

`((epsi_(Q))/(epsi_(p)))^(4) theta_(p)`

Text Solution

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The correct Answer is:
B
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