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The correct curve between log(e) R and l...

The correct curve between `log_(e) R` and `log_(e) (theta - theta_(o)`) is -

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To solve the problem, we need to establish the relationship between the logarithm of the rate of cooling (log_e R) and the logarithm of the difference between the temperature of the body (theta) and the surrounding temperature (theta_o). ### Step-by-Step Solution: 1. **Understanding the Variables**: - Let \( R \) be the rate of cooling, defined as \( R = -\frac{dT}{dt} \) (the negative sign indicates cooling). - Let \( \theta \) be the absolute temperature of the body. - Let \( \theta_o \) be the temperature of the surroundings. 2. **Applying Newton's Law of Cooling**: - According to Newton's Law of Cooling, the rate of cooling can be expressed as: \[ R = k (\theta - \theta_o) \] where \( k \) is a constant of proportionality. 3. **Taking the Natural Logarithm**: - We take the natural logarithm (log_e) of both sides: \[ \log_e R = \log_e [k (\theta - \theta_o)] \] - Using the properties of logarithms (specifically the product rule), we can expand the right side: \[ \log_e R = \log_e k + \log_e (\theta - \theta_o) \] 4. **Rearranging the Equation**: - This can be rearranged to: \[ \log_e R = \log_e (\theta - \theta_o) + \log_e k \] - This is in the form of a linear equation \( y = mx + c \), where: - \( y = \log_e R \) - \( x = \log_e (\theta - \theta_o) \) - \( m = 1 \) (the slope) - \( c = \log_e k \) (the y-intercept) 5. **Analyzing the Graph**: - Since \( k \) is a positive constant, \( \log_e k \) is also positive. - The slope \( m = 1 \) indicates that the graph is a straight line with a positive slope. - The y-intercept is positive, confirming that the line will cross the y-axis above the origin. 6. **Conclusion**: - The relationship between \( \log_e R \) and \( \log_e (\theta - \theta_o) \) is linear, with a positive slope and a positive intercept. Therefore, the correct curve is a straight line that rises from left to right. ### Final Answer: The correct curve between \( \log_e R \) and \( \log_e (\theta - \theta_o) \) is a straight line with a positive slope and a positive y-intercept.
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