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The two ends of a rod of length `L` and a uniform cross-sectional area `A` are kept at two temperature `T_(1)` and `T_(2)` `(T_(1) gt T_(2))`. The rate of heat transfer. `(dQ)/(dt)`, through the rod in a steady state is given by

A

`(dQ)/(dt) = (kA(T_(1) - T_(2)))/(L)`

B

`(dQ)/(dt) = (kL (T_(1) - T_(2)))/(A)`

C

`(dQ)/(dt) = (k(T_(1) - T_(2)))/(LA)`

D

`(dQ)/(dt) = KLA (T_(1) - T_(2))`

Text Solution

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A
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