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A liquid in a beaker has temperature the...

A liquid in a beaker has temperature `theta(t)` at time t and `theta_0` is temperature of surroundings, then according to Newton's law of cooling the correct graph between `log_e( theta-theta_0)` and t is :

A

B

C

D

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The correct Answer is:
C
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MOTION-HEAT TRANSFER & THERMAL EXPANSION -Exercise - 3 Section-B
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