In 0.1 M solution of a non electrolyte, `Psi_W` value will be :

Options

A. zero bar
B. `+2.3` bar
C. `-2.3 ` bar
D. ` -22.4` bar

Answer

To find the water potential (Ψw) of a 0.1 M solution of a non-electrolyte, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Water Potential**:
- Water potential (Ψw) is a measure of the potential energy of water in a system and is influenced by solute concentration and pressure. The formula for calculating water potential is:
\[ Ψ_w = -iCRT \]
- Where:
- \(i\) = ionization constant (for non-electrolytes, \(i = 1\))
- \(C\) = molar concentration of the solution
- \(R\) = pressure constant (0.0831 liter bar per mole per Kelvin)
- \(T\) = temperature in Kelvin

2. **Identify Given Values**:
- For a 0.1 M solution of a non-electrolyte:
- \(C = 0.1 \, \text{M}\)
- \(i = 1\) (since it is a non-electrolyte)
- \(R = 0.0831 \, \text{L bar K}^{-1} \text{mol}^{-1}\)
- Assume standard temperature \(T = 273 \, \text{K}\)

3. **Plug Values into the Formula**:
- Substitute the values into the water potential formula:
\[ Ψ_w = -iCRT = -1 \times 0.1 \times 0.0831 \times 273 \]

4. **Calculate the Result**:
- First, calculate the product:
\[ 0.1 \times 0.0831 \times 273 = 2.27303 \]
- Therefore:
\[ Ψ_w = -2.27303 \, \text{bar} \]

5. **Final Answer**:
- The water potential (Ψw) of a 0.1 M solution of a non-electrolyte is approximately:
\[ Ψ_w \approx -2.3 \, \text{bar} \]