`P=(124-32sqrt(15))^(1/4), \ q=(x^4+1/(x^4));` where `x=sqrt(3+2sqrt(2)),` then `((q-p^2)/(sqrt(15)))` is

If x=sqrt(2+sqrt(2)), then x^(4)+(1)/(x^(4)) is

(1)/(sqrt(15+4x-4x^(2)))

If P=2+sqrt3 , Q=2-sqrt3 , then P/Q=?

If I=int(sinx+sin^3x)/(cos2x)dx=Pcosx+Qlog|f(x)|+R , then (a) P=1/2,Q=-3/(4sqrt(2)) (b) P=1/4, Q=1/(sqrt(2)) (c) f(x)=(sqrt(2)cosx+1)/(sqrt(2)cosx-1) (d) f(x)=(sqrt(2)cosx-1)/(sqrt(2)cosx+1)

If I=int(sinx+sin^3x)/(cos2x)dx=Pcosx+Qlog|f(x)|+R , then (a) P=1/2,Q=-3/(4sqrt(2)) (b) P=1/4, Q=1/(sqrt(2)) (c) f(x)=(sqrt(2)cosx+1)/(sqrt(2)cosx-1) (d) f(x)=(sqrt(2)cosx-1)/(sqrt(2)cosx+1)

Solve for x:sqrt(2x-1)+sqrt(3x-2)=sqrt(4x-3)+sqrt(5x-4)

sqrt(x^(p-q))sqrt(x^(q-r))sqrt(x^(r-p))=1

If I=int(sin x+sin^(3)x)/(cos2x)dx=P cos x+Q log|f(x)|+R then (a)P=(1)/(2),Q=-(3)/(4sqrt(2))(b)P=(1)/(4),Q=(1)/(sqrt(2)) (c) f(x)=(sqrt(2)cos x+1)/(sqrt(2)cos x-1)(d)f(x)=(sqrt(2)cos x-1)/(sqrt(2)cos x+1)

If P and Q are two points on the circle x^2 + y^2 - 4x + 6y-3=0 which are farthest and nearest respectively from the point (7, 2) then. (A) P-=(2-2sqrt(2), -3-2sqrt(2)) (B) Q-= (2+2sqrt(2), -3 + 2 sqrt(2)) (C) P-= (2+2sqrt(2), -3 + 2 sqrt(2)) (D) Q-= (2-2sqrt(2), -3 + 2 sqrt(2))

If P and Q are two points on the circle x^2 + y^2 - 4x + 6y-3=0 which are farthest and nearest respectively from the point (7, 2) then. (A) P-=(2-2sqrt(2), -3-2sqrt(2)) (B) Q-= (2+2sqrt(2), -3 + 2 sqrt(2)) (C) P-= (2+2sqrt(2), -3 + 2 sqrt(2)) (D) Q-= (2-2sqrt(2), -3 + 2 sqrt(2))