" 2."x-y=3;(x)/(3)+(y)/(2)=6

Solve for x and y : ( 3x )/( 2) - ( 5y )/( 3) = - 2, ( x)/(3) + ( y)/(2) = (13)/(6)

Find the values of x&y when (2x)/(3)+(y)/(2)=3 and (x)/(2)-(2y)/(3)=(1)/(6)

If (x+3)/(4)=5 and (y-2)/(3)=6 then x and y are:

Solve for x and y : (x, y ne 0) (10)/(2x+y)+(3)/(2x-y)=3, (15)/(2x+y)+(9)/(2x-y)=6

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

4x-2y=3 6x-3y=5

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

Simplify: (x+y)^(3)-(x-y)^(3)-6y(x^(2)-y^(2))