Two circles have equations `x^(2)+y^(2)-4x-6y-7=0` and `x^(2)+y^(2)-2x-3=0` then

The circles x^(2)+y^(2)-4x-6y-12=0 and x^(2)+y^(2)+4x+6y+4=0

. The centres of the circles x^(2)+y^(2)-6x-8y-7=0 and x^(2)+y^(2)-4x-10y-3=0 are the ends of the diameter of the circle

Find the limiting points of the system of the co-axial circles determined by the x^(2)+y^(2)-4x-6y=3=0 and x^(2)+y^(2)-24x-26y+277=0

If a circle having centre at (alpha,beta) cut the circles x^(2)+y^(2)-2x-2y-7=0 and x^(2)+y^(2)+4x-6y-3=0 orthogonally,then |(3)/(4)alpha-(beta)/(2)| is equal to

One of the limit point of the coaxial system of circles containing x^(2)+y^(2)-6x-6y+4=0, x^(2)+y^(2)-2x-4y+3=0 , is

The two circles x^(2)+y^(2)-2x-3=0 and x^(2)+y^(2)-4x-6y-8=0 are such that