13 . `sec 2 ( θ − α ) 1 2 cos e c 2 θ sec 2 ( θ + α )` a r e ∈ H . P . t h e n : A ) `−π/4 < α < π/4` B ) `−π/2 < α < π/2` C ) `3π/4 < α < 5π/4` D ) `5π/4 < α < 7π/4`

Sec^2θ + cosec^2θ = sec^2θ * cosec^2θ

cos2θ* cos(θ/2) - cos3θ*cos((9θ)/2) = sin5θsin((5θ)/2)

(sinθ - 2sin^3θ)/(2cos^3θ - cosθ) = tanθ

The value of (sec^(2)θ /cosec^(2)θ) + (cosec^(2)θ /sec^(2)θ )-(sec^(2)θ + cosec^(2)θ) is : (sec^(2)θ /cosec^(2)θ) + (cosec^(2)θ /sec^(2)θ )-(sec^(2)θ + cosec^(2)θ) का मान बराबर है :

If cotθ = sqrt6 , then the value of is: (cosec^(2)θ + sec^(2)θ)/(cosec^(2)θ − sec^(2)θ) यदि cotθ = sqrt6 है तो (cosec^(2)θ + sec^(2)θ)/(cosec^(2)θ − sec^(2)θ) का मान हैः

If ((sinθ−cosecθ)(cosθ−secθ))/(tan^(2)θ -sin^(2)θ) = r^3 , then r=? यदि ((sinθ−cosecθ)(cosθ−secθ))/(tan^(2)θ -sin^(2)θ) = r^3 है तो r बराबर हैः

Trigonometric identities with proOF || Multiplicative inverse || Sin2θ + cos2θ =1 || sec2θ -tan2θ =1 || cosec2θ -cot2θ =1 || Exemplar questions discussion

If 2sec^2A-sec^4A-2cos e c^2A+cos e c^4A=(15)/4,t h e n tan A is equal 1//sqrt(2) (b) 1/2 (c) 1/2sqrt(2) (d) -1/(sqrt(2))

Solve, integrate ∫ (dθ)/(sin^2θ * cos^2θ)