Paragraph- Two particles are projected simultaneously from the top of a tower of height 80m horizontally in mutually perpendicular directions at equal speed of 40m/s. Q.The relative velocity of particles when they strike the ground is: m/s

A body is projected horizontally from the top of a tower of height 10m with a velocity 10m/s .Its velocity after 1 second is

A particle is projected upwards from the roof of a tower 60 m high with velocity 20 m//s. Find (a) the average speed and (b) average velocity of the particle upto an instant when it strikes the ground. Take g= 10 m//s^2

A particle is dropped from the top of a tower of height 80 m . Find the time of jurney and the speed with which it strikes the ground.

Two particles are projected with speed 4m//s and 3m//s simultaneously from same point as shown in the figure. Then:

Two particles A and B are projected simultaneously from the two towers of height 10m and 20m respectively.Particle A is projected with an initial speed of 10sqrt2m//s at angle of 45^(@) with horizontal, while particle B is projected horizontally with speed 10m//s .If they collide in air, wht is the distance d between the towers?

Two particles are projected with speed 4 m//s and 3 m//s simultaneously from same point as shown in the figure. Then :

Two particles A and B are projected simultaneously from two towers of heights 10 m and 20m respectively. Particle A is projected with an initial speed of 10 sqrt(2) m//s at an angle of 45^@ with horizontal, while particle B is projected horizontally with speed 10 m//s . If they collide in air, what is the distance d between the towers?

Two particles are projected from a tower horizontally in opposite directions with velocities 10 m//s and 20 m//s . Find the time when their velocity vectors are mutually perpendicular. Take g=10m//s^2 .

A particle is projected vertically upward in vacum with a speed 40m//s then velocity of particle when it reaches at maximum height 2s before, is (Take g=10m//s )

A particle of mass 50 g is projected horizontally from the top of a tower of height 50 m with a velocity 20m//s . If g=10m//s^(2) , then find the :-