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When Cl(2) is treated with Na(2)S(2)O(3)...

When `Cl_(2)` is treated with `Na_(2)S_(2)O_(3)` the oxidation state of sulphur in the product is x .When `I_(2)` is treated with `Na_(2)S_(2)O_(3)` the oxidation state of sulphur in the product is y what is (x+2y)/(11)

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