" A particle is moving in "X-Y" plane such that "x=2t" and "y=5sin(2t)." Then maximum speed of particle is: "

A particle is moving in X-Y plane that x=2t and y=5sin(2t). Then maximum speed of particle is:

The coordinates of a particle moving in XY-plane vary with time as x= 4t^(2), y= 2t . The locus of the particle is a : -

The coordinates of a particle moving in XY-plane very with time as x=4t^(2),y=2t . The locus of the particle is

The coordinates of a particle moving in XY-plane at any instant of time t are x=4t^(2),y=3t^(2) . The speed of the particle at that instant is

A particle is moving in x-y plane with y=x/2 and V_(x)=4-2t . The displacement versus time graph of the particle would be

A particle moves in x-y plane according to equations x = 4t^(2)+5t and 6y=5t The acceleration of the particle must be

The co-ordinates of a moving particle at any time t are given by x=ct^(2) and y=bt^(2) The speed of the particle is

The coordinates of a particle moving in x-y plane at any time t are (2 t, t^2). Find (a) the trajectory of the particle, (b) velocity of particle at time t and (c) acceleration of particle at any time t.

The co-ordinate of the particle in x-y plane are given as x=2+2t+4t^(2) and y=4t+8t^(2) :- The motion of the particle is :-

A particle moves in xy plane such that v_(x)=50-16 t and y=100-4t^(2) where v_(x) is in m/s and y is in m. It is also known that x=0 when t=0 . Determine (i) Acceleration of particle (ii) Velocity of particle when y=0 .