Q. 11 The solution of (dy)/(dx)=(2x-y+3)/(x+2y+4) is y^(2)-x^(2)+xy+4y-3x+1=C x^(2)-y^(2)+xy+4y+3x-1=C y^(2)-x^(2)-xy-4y+3x-1=C y^(2)-x^(2)+xy+4y-3x-1=C

Solution of D.E (dy)/(dx)=(2x+5y)/(2y-5x+3) is,if (y(0)=0) (1) x^(2)-y^(2)+5xy-3y=0 (2) x^(2)+y^(2)+5xy-3y=0 (3) x^(2)-y^(2)+5xy+3y=0 (4) x^(2)-y^(2)-5xy-3y=0

12xy (9x ^ (2) -16y ^ (2)) -: 4xy (3x + 4y)

The solution of the differential equation (dy)/(dx)=(3x^(2)y^(4)+2xy)/(x^(2)-2x^(3)y^(3)) is

The solution of ((dy)/(dx))^(2)+(2x+y)(dy)/(dx)+2xy=0, is (i) (y+x^(2)-c_(1))(x+log y+y^(2)+c_(2))( (ii) (y+x^(2)-c_(1))(x-log y-c_(2))( iii) (y+x^(2)-c_(1))(x+log y-c_(2))( iv) (y+x^(2)-c_(1))(3x+log y-c_(2))

Add: 4x^(2) - 7xy + 4y^(2) - 3, 5 + 6y^(2) - 8xy + x^(2) and 6 - 2xy + 2x^(2) - 5y^(2)

If x^(4) + y^(4)=19 and x+y=1 find x^(2)y^(2)-2xy

Solve for x and y:3x^(2)-5y^(2)=7,3xy-4y^(2)=2

Simplify : 3x^(2)+4xy^(2)+y^(3)-2y^(2)x+3x(x^(2)+y^(2))

Subtract the sum of 7x^(2) - 4y^(2) " and " 4x^(2) + 3xy - 4y^(2) from the sum of 5x^(2) - 3xy - y^(2) "and " x^(2) + 2xy - 2y^(2) .